Math Question: What is the sum of all numbers from 99 to 500 (inclusive), if each even number is multiplied by 3 and each odd number is divided by 2?

To find the sum, we first calculate the sum of the even numbers from 99 to 500, and the sum of the odd numbers from 99 to 500. For even numbers, we have the sequence 102, 105, 108, ..., 498. The common difference is 3, and using the formula for arithmetic series, we obtain (498-102)/3 + 1 = 133 even numbers. The sum of these even numbers is (102+498)/2 * 133 = 30015. Next, for odd numbers, the sequence is 99, 101, 103, ..., 499. The common difference is 2, and the number of odd numbers is (499-99)/2 + 1 = 201. The sum of all odd numbers is (99+499)/2 * 201 = 75525. Finally, we add the sum of even and odd numbers to get the overall sum: 30015 + 75525 = 105540. Therefore, the sum of all numbers from 99 to 500, with the given conditions, is 105540.

Math question: What is the sum of the first 50 odd numbers starting from 99?

The first 50 odd numbers starting from 99 can be calculated using the formula 2n - 1, where n represents the position of the number in the sequence. So, the first number is 99, the second is 101, the third is 103, and so on. By plugging in the respective values of n into the formula, we can find the 50th number, which is 197. To find the sum of these numbers, we can use the formula for the sum of an arithmetic series, Sn = (n/2)(a+l), where Sn represents the sum, n is the number of terms, a is the first term, and l is the last term. In this case, n = 50, a = 99, and l = 197. Substituting the values into the formula, we get Sn = (50/2)(99+197) = 25 * 296 = 7,400. Therefore, the sum of the first 50 odd numbers starting from 99 is 7,400.

Math Question: What is the sum of three consecutive even numbers with 99 as the middle number?

Let's represent the three consecutive even numbers as n-2, n, and n+2. As per the question, the middle number is 99. Therefore, n = 99. Plugging in this value, the numbers become 97, 99, and 101. To find the sum, add these three even numbers together: 97 + 99 + 101 = 297 Hence, the sum of three consecutive even numbers with 99 as the middle number is 297.

Max	9223372036854775807
25835	Positive integer
0b10001100	Binary number
01771452	Octal number
0x129abf	Hex number
5.012 * 10^7	Scientific notation
2^4 * 5	Factorized form
*	Random number

99 (number)

99 is an odd 2-digits composite number following 98 and preceding 100. In scientific notation, it is written as 9.9 × 10^1. The sum of its digits is 18. It has a total of 3 prime factors and 6 positive divisors. There are 60 positive integers (up to 99) that are relatively prime to 99.

Interesting facts

99 has 6 divisors, whose sum is 156
The reverse of 99 is 99
Previous prime number is 3

Basic properties

Is Prime? no
Number parity odd
Number length 2
Sum of Digits 18
Digital Root 9

Name

Name	ninety-nine

Notation

Scientific notation	9.9 × 10^1
Engineering notation	9.9 × 10^0

Prime Factorization of 99

Prime Factorization 3 × 3 × 11

Composite number

ω	Distinct Factors	2	Total number of distinct prime factors
Ω	Total Factors	3	Total number of prime factors
rad	Radical	33	Product of the distinct prime numbers

The prime factorization of 99 is 3 × 3 × 11. Since it has a total of 3 prime factors.

Most popular turbo-numbers

9, 2, 70, 65, 139, 659, 8235, 5595, 20380, 85803, 832530, 232341, 7698211, 19564, 95998058, 59806197, 389134905, 151822612, 7154270911, 3236847649

Basic calculations (n = 99)

Multiplication

n×y

n×2	198
n×3	297
n×4	396
n×5	495

Division

n÷y

n÷2	49.5
n÷3	33
n÷3	24.75
n÷5	19.8

Exponentiation

n^y

n²	9801
n³	970299
n⁴	96059601
n⁵	9509900499

Nth Root

^y√n

²√n	9.9498743710662
³√n	4.6260650091827
⁴√n	3.1543421455299
⁵√n	2.5068424421341

Divisors of 99

1, 3, 9, 11, 33, 99

6 divisors

τ	Total Divisors	6	Total number of the positive divisors of n
σ	Sum of Divisors	1	Sum of all the positive divisors of n
s	Aliquot Sum	-98	Sum of the proper positive divisors of n
A	Arithmetic Mean	0.16666666666667	Returns the sum of divisors (σ(n)) divided by the total number of divisors (τ(n))
G	Geometric Mean	1	Returns the nth root of the product of n divisors
H	Harmonic Mean	6	Returns the total number of divisors (τ(n)) divided by the sum of the reciprocal of each divisors

The number 99 can be divided by 6 positive divisors. The sum of these divisors (counting 99) is 1, the average is 0.16666666666667.

Base conversion 99

Base	System	Value
2	Binary	1100011
3	Ternary	10200
4	Quaternary	1203
5	Quinary	344
6	Senary	243
8	Octal	143
10	Decimal	99
12	Duodecimal	83
16	Hexadecimal	63
20	Vigesimal	4j
36	Base36	2r

Cryptographic Hash Functions

md5	ac627ab1ccbdb62ec96e702f07f6425b
sha1	9a79be611e0267e1d943da0737c6c51be67865a0
sha256	8c1f1046219ddd216a023f792356ddf127fce372a72ec9b4cdac989ee5b0b455
sha512	6781a9e05f5e327a138f3d09ce0211ce4f166d940a14b46373e44402a3f3754cab4109f62c50777cbc1e3c4f1b8e6234e8d0b41281571bf0e1bd480c12149830
ripemd-160	ebf8511e3ecae777d92be0b44471f67ee992c53d

99 as geometric shapes

Circle

Radius = n

Diameter	198
Circumference	622.03534541078
Area	30790.749597834

Sphere

Radius = n

Volume	4064378.946914
Surface area	123162.99839133
Circumference	622.03534541078

Square

Length = n

Perimeter	396
Area	9801
Diagonal	140.00714267494

Cube

Length = n

Surface area	58806
Volume	970299
Space diagonal	171.47302994932

Equilateral Triangle

Length = n

Perimeter	297
Area	4243.9574912456
Altitude	85.736514974659

Triangular Pyramid

Length = n

Surface area	4243.9574912456
Volume	114350.83377975
Height	46.669047558312